A solution of CuCO3 has a [Cu2+] - 1.5 x 10 negative 5 and [ co3 to the 2-] = 3.2 x 10 to the negative 6?

if CuCO3 has Ksp = 2.5 x 10 to the negative 10, determine wheather a precipitate will form in this solution

Answer:
can u please improve the question as i jus cant make out d question itself.. u can wait for some time if anyone identifies it.. or else do repost d question wid a little more explanation as its really difficult to understant it..

The conditions for the equilibrium

CuCO3 <> Cu2+ + CO32-

is that

Ksp = [ Cu2+] [ CO32-] = 2.5 x 10^-10

if the product of [Cu2+] times the carbonate concentration is greater than Ksp CuCO3 should precipitate

1.5 x 10^-5 ( 3.2 x 10^-10)= 4.8 x 10^-15

Since the ion-product is less than Ksp it means we do not have enought concentration of Cu2+ and CO32- to form a saturated solution. We do not expect precipitation to occur

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A solution of CuCO3 has a [Cu2+] - 1.5 x 10 negative 5 and [ co3 to the 2-] = 3.2 x 10 to the negative 6?

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