Give the pH of a solution when [H3O^+]=7.8 x 10^(-)6M?
Answer:
pH = -log [H3O+]
so pH = -log (7.8 x 10^-6)
pH = 5.1, slightly acidic
5.11
pH = -log [H3O+] = log 1/[H3O+]
The pH equation is:
pH = -log [H+],
where [H+] is the concentration of Hydrogen ions in the solution. In a water solution, H3O+ is the same as H+.
So the pH of the solution is -log (.0000078) = 5.11
ur mom!, jk the answer is H3O=^34[6M]
The pH of the solution you describe is 5.1
The log of any number less than 1 (and greater than 0) is going to be negative. Therefore, if you have a very high concentration of H3O+ (ie above 1 M) the log will be negative, giving you a possitive pH.
pH = the - log of the hydrogen ion concentration.
[ ], means concentration of. M (Molarity) also means concentration.
H30+ is the hydrogen ion.
So, the equation is as follows:
-log [H30+]
or
-log 7.8 x 10^ -6
This equals I don't have a calculator
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