Calculating molarity?

A sample of Sodium Chloride solution has a total mass of 51.623 grams of NaCL in a total volume of 834.21mL of solution. Calculate molarity?

Answer:
Molecular weight NaCl = 58.45 g/mol
51.623 g / 58.45 = 0.8831 moles NaCl
834.21 mL = 0.83421 L
M = 0.8831 / 0.83421 = 1.0587 M

Atomic weights: Na=22.989 Cl=35.453 NaCl=58.442
Let the solution be called S

51.623gNaCl/834.21mLS x 1molNaCl/58.442gNaCl x 1000mLS/1LS = 1.0589 molNaCl/1LS

divide 51.623 by the molar mass of NaCl (something like 22.98977 + 35.453, not sure about that); now take that number, which is the moles of NaCl and divide by .83421 Litres.

M=mol/vol

so you must convert the grams to moles.
51.623 NaCl/58g=0.890 mol

convert mL to L-----> 0.83421L

0.890 / 0.83421 = 1.06

M= 1.06

51.623*1000/(58.5*834.21)

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Calculating molarity?

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