How many number of atoms are there in 1 gram of acetic acid?
Answer:
1 g CH3CO2H MW = 60.05 g/mol
= 0.0167 mole
0.0167 mole * 6.023 *10^23 molecules/mole =
= 1.00*10^22 molecules
each molecule has eight atoms
so there are 8.00* 10^22 atoms
Acetic acid formula = CH3-COOH
The molecular mass is (12+3) + (12 + (16 x 2 ) + 1 ) = 60
Using n = m/Mr to find the number of moles
n = 1 / 60 = 0.0017 moles
Using Avagardo's number 1 mole of substance = 6.02 x 10^23 molecules
Therefore no. of molecules= (0.0017 x 6.02 x 10^23)
= 1.00 x 10^22 molecules
Each molecule has 8 atoms hence no of atoms = 8.00 x 10^22 atoms
Apply avogadros number which is 6.02 * 10 ^23 atoms
is a mole and the rule that the atomic weight of the
chemicals modecule ,or the elements modecule
determines how many grams of mass a mole of the chemical compund or element will
have .
CH3COOH
count how many elements are there:
2*C+4*H+2*O = 8
so one mol contains 8 moles of atoms
wht is the molecular weight for the acetic acid
60.05 g/mol
1g/60.05(g/mol) = 0.017 mol
0.017 mol acetic acid * (8 moles of atoms)/(1 mol acetic acid) = 0.133 mole atoms
1 mol = 6*10^23
0.133*6*10^23= 8*10^22
The answers post by the user, for information only, FunQA.com does not guarantee the right.
More Questions and Answers: