Molarity Question?

2.50 L of a 2.27 M solution of Ba(NO3)2 is how many grams?

Answer:
Do you mean grams of Ba(NO3)2?

2.27 M means 2.27 moles per liter. If you have 2.5 liters, you have 2.5 x 2.27 = 5.68 moles of barium nitrate
The molecular mass of barium nitrate is 261.336 g/mol
5.68 moles of barium nitrate = 261.336 g/mol x 5.68 mol = 1484.39 grams
Multiply 2.5 by 2.27 to find the number of moles.
Then, add together 137.34, 28, and 96 and multiply the sum by the number of moles.
molarity=moles/liter
2.27=moles/2.50
moles=2.50*2.27
moles=5.675
moles=# of g /moleculer wt
# of grams=mol wt *moles
=261*5.675
=1481.175 g
Your answers are way too long.

g= M*MW*L = 2.27* 2.50* 261
= 1481.175 (1.48 * 10^3 in sci. notation)

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