Chemistry help?

a roll of aluminum foil sold in the supermarket is 66 2/3 yards by 12 inches. It has a mass of 0.83 kg. If the density of aluminum foil is 2.70 g/ cm^3, what is the thickness of the foil in inches?

Answer:
662/3 yards is 200 feet.
The area of the foil is 200 sq feet
D=mass/volume
.83 kg=830 grams
2.7=830 grams/volume
v=30.7 ml
volume=area X height or thickness
you need to change 200 sq ft to metric to continue.
Marvellous question for checking on units!

The size of the aluminium foil is 200 feet X 1 Feet X thickness
Take a foot as 30.48cm and the size is 6096 * 30.48 * x cm^3
So its weight is 6096 * 30.48 * 2.70/1000 * x = 0.83

This gives x as .001654 cm which is 6.5 *10^-4 inches

(Just checked online and found some foil advertised at a thickness of .0025cm so it seems reasonable)
Let's get it all to cm first

2/3 yards = 0,667 yards

66 + 0,667 = 66,667 yards

1 yd = 91,44 cm ---> 66,667 yd = 6096,031 cm

1 inch = 2,54 cm

12 inches = 12 * 2,54 = 30,48 cm

density of foil * dimensions = 0,83 kg = 830 g

Let's say thickness is "t"

2,70 * 6096,031 * 30,48 * t = 830
t= 1,65 * 10^(-3) cm = 6,49 * 10^(-4) inches

Hope this helps..!
We are solving for height (remember length x width x height = volume). 2.70 g/cm^3 is a measurement of volume. So before we can solve for height all data needs to be in the metric system. 66 2/3 yards is equal to 6095.99 centimeters. and 12 inches is equal to 30.48 cm, also 0.83 kg is 830 grams. Alright now the math, let H equal the thickness of the foil:

830 g / (6095.99 cm x 30.48 cm x H) = 2.70 g / 1 cm^3
Isolate H:

H = (830 g / (6095.99 cm x 30.48 cm)) / (2.70 g / 1 cm^3)

Plug it into a calculator:

H = 0.00165 cm

Convert to inches: (2.54 cm in 1 inch)

0.00165 cm / 2.54 cm = 0.000650 inches or 6.50 x 10^-4

Remember, only 3 sig figs!

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Role of analytical chem?classification of analytical methods?
  • Why should the cork and the glass tubing be moistened with water?
  • I need help with this problem?
  • Can matches light without the presence of oxygen?
  • Is there any elements or componds harder than dimemonds?
  • Does anyone know any websites or online video discussing the atomic structure/energy/parts of an atom?
  • A cubical block of ice floating in water has to support a metal piece weighing 0.5kg what can be the minimum?
  • Maldi tof peak analysis at 827.61,871.63,953.54, 666.12,681.66 nm of microcystin?
  • Extreme chem challenge!!. =p?