What mass of KHP would be neutralized with 28.00 ml of 0.4824M NaOH?



Answer:
Moles NaOH = 28 x 0.4824 /1000 = 0.01351 = moles KHP
Molecular weight KHP = 204.22 g/mol
0.01351 mol x 204.22 g/mol = 2.758 g KHP needed

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