50 g of sugar (C12H22O11)is dissolved in500g water at standard pressure.How much is the freezing point lowered



Answer:
delta T =KfXmXi
Kf=1.86
i=1
delta T=1.86X50X5000/342X500
=0.544
wrong question, freezing point will go more after dissolving sugar,salt etc
ΔTf = i · Kf · m

i = 1
Kf = -1.86

m is the activity. Figure that out and you are golden.

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