Electrochemistry 3?
In galvanic cell, why does anode, where the oxidation occurs, gets more positive and why does cathode, where the reduction occurs, gets more negative as the reaction proceeds?
I know that Ecell = -Ecathode + Eanode, which becomes
Ecell = Ecathode - Eanode...
but I don't get the relationships between being a better reducing agent/oxidizing agent and the Ecell value.
PLEASE answer these questions!!!
Answer:
The anode gets more positive because electrons are leaving the electron rich anode (which carries a negative charge to begin) and going to the cathode. Just like a battery the cell proceeds to a neutral charge equilibrium (which occurs when the cell runs out of charge or "dies"). A better oxidizing agent has a high standard reduction electrode half-cell potential, whereas a better reducing agent has a *low* standard reduction electrode half-cell potential. This is because the oxidation reaction is the negative of the reduction half-cell value. Thus Ecell = Ecathode (high) - Eanode (low) makes a good cell that has a high Ecell. Hope this helps.What is the final oxidation product of methanol when subjected to an excess of aq. KMnO4?
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I know that Ecell = -Ecathode + Eanode, which becomes
Ecell = Ecathode - Eanode...
but I don't get the relationships between being a better reducing agent/oxidizing agent and the Ecell value.
PLEASE answer these questions!!!
Answer:
The anode gets more positive because electrons are leaving the electron rich anode (which carries a negative charge to begin) and going to the cathode. Just like a battery the cell proceeds to a neutral charge equilibrium (which occurs when the cell runs out of charge or "dies"). A better oxidizing agent has a high standard reduction electrode half-cell potential, whereas a better reducing agent has a *low* standard reduction electrode half-cell potential. This is because the oxidation reaction is the negative of the reduction half-cell value. Thus Ecell = Ecathode (high) - Eanode (low) makes a good cell that has a high Ecell. Hope this helps.