Consider the reaction of S2O8^2- ions with I^ - inons for which of the following mechanism?

Consider the reaction of S2O8^2- ions with I^ - inons for which of the following mechanism
Cu^(2+) +I^- >>> Cu(+) + I fast
2I>>> I2 fast
Cu^(+)+ S2O8^2- >>> CuSO4^+ +SO4^(2-) Slow
Cu^(+)+ CuSO4^+ >>>> 2Cu^(2+) + SO4^(2-) Fast

Also explain what effect increasing [I-] would have on the overal rate , also effect of increasing [S2O8^2- ] on the rate?

Answer:
As you haven't mentioned which reactions are in equilibrium, I have assumed that all of them are spontaneous and one way.

The overall speed of the reaction depends on that of the slow steps involved. The only slow step involved in this synthesis is #3.

Look at the reaction,
Cu(+) + S2O8(-2) -----> CuSO4 + SO4(-2)

Here we need to increase the concentration of Cu(+) and/or S2O8(-2) to increase the speed of the reaction overall. So, the increasing of [S2O8(-2)] will increase the rate of the reaction.

On the other hand, the increase of [I(-)] will have no effect on the rate of the reaction, as it is not directly involved in the slowest step and all the other steps are not in equilibrium.

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