Help! Calculate Values of Ka, Pka for acetic acid.?

0.42% of acetic acid molecules in 1.0 M solution are ionized at 25 celcius. Calculate values of Ka, and pKa for acetic acid.

Answer:
Since percent ionization equals the concentration upon ionization over the initial concentration of the acid, multiplied by 100%, you can get the value of the concentration of H+ upon ionization by substituting values... 0.0042*1M, as I think.
One you know that value, you can get the concentration of acetate anions which is equal to that of the H+ in solution. You can also get the concentration of non-dissociated acetic acid by subtracting the concentration that dissociated from 1M (if that 1M is the initial concentration of acetic acid)...

You can now get the Ka...
You can get the pKa by getting using this:
-log (Ka)
Just like the way you get pH.

I hope that helped you.
turn 25 celcius to kalvin (add 273) and then plug in your numbers into the formula../ which I forgot the formula...
Degree of dissociation = alpha = root (Ka/C).

So 0.0042 = root Ka.

So you can now work out Ka and the rest.

The answers post by the user, for information only, FunQA.com does not guarantee the right.



More Questions and Answers:
  • Dissolving common salt in water is a chemical change or a physical change and give reasons?
  • Depict the electron configuration for the low spin cobalt complex [Co(NH3)6]3+?
  • Specific heat?
  • When the concentration of a reactant is increased which of the following is true?
  • When making ice cream, the temperature of the ingredients is decreased to below the freezing pt. pf pure water
  • What does salt do?
  • Why is this done with a watchglass rather than a piece of filter paper?
  • What's the chemical formula for bauxite?
  • Chem math problems please help me if you can?