Writing formulas for alkyle halides?

1) 1,1-dicholoro-1-propene
2) 1,2,3-trichloro-2-methylbutane
3) trans-2,3-dibromo-2-butene
4) 1,2,4-tribromoheptane
5) 1,2,3-tricholoro-4-methyl-1,3-...
6) 2-boromo-2-chloro-1,1,1-triflo...
7) cis-1,2-difluoro-1-iodo-1-bute...
8) 2,2-dibromo-3-methylhexane
9) 3,3-diiodo-1-pentyne
10) 1,1,4,4-tetrafluoro-2,3-diiodo...
11) cis-2,3-dichloro-2-butene
12) 1,1,4-triiodo-3,3,5-trimethylh...

Answer:
1.Cl2C=CH-CH3

CH3
I
2.H2C-C-CH-CH3
I I I
Cl Cl Cl

Br
I
3.H3C-C=C-CH3
I
Br

4.H2-CH-CH-CH2-CH-CH2-CH2-CH3
I I I
Br Br Br

5.
see my answer for alkynes

1. draw the base chain
2. Add in double bonds
3. Add in halides (group seven)
di - two of a kind, may be on different atoms
tri - three of a kind
tetra - four of a kind

chloro = chlorine = Cl
iodo = I
fluoro = F

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