How to measure the weight of Hg(NO3)2 to make ppm solution of it when it is in liquid form?
Answer:
Before this question can be answered, some assumptions must be made about the solutions be used and created. It will be assumed that when you say "in liquid form" that you mean in aqueous solution.
1) The concentration and density of the Hg(NO3)2 solution
2) The concentration (ppm) of the solution to be made
3) The volume (L) of the solution to be made.
For this example I will use "given" values, although your values will most likely be different.
1) The Hg(NO3)2 solution is 0.277M with a density of 1.05 g/mL
2) The concentration of the resulting solution will be 425 ppm
3) The volume of the resulting solution will be 1.58L
First, determine the concentration(M) of your resulting solution.
425 ppm = 425mg Hg(NO3)2 / kg solution assume density = 1.00g/mL
425 mg Hg(NO3)2 / kg (1g / 1000 mg)(1kg / L)(1 mol Hg(NO3)2 / 324.62 g)
= 1.31x10-3 M (solution to be made)
Second, determine the volume of the original Hg(NO3)2 solution needed to make 1.58L of 425 ppm solution.
Use the equation McVc = MdVd Solve for Vc
Mc - molarity of the starting Hg(NO3)2 solution
Vc - volume of the starting Hg(NO3)2 solution
Md - molarity of the 425 ppm Hg(NO3)2 solution
Vd - volume of the 425 ppm Hg(NO3)2 solution
(0.277M)(Vc) = (1.58L)(1.31x10-3M) Vc = 7.47x10-3 L = 7.47 mL
Finally, use the density of the starting Hg(NO3)2 solution to determine the mass of the Hg(NO3)2 solution needed.
7.47mL (1.05g / mL) = 7.84 g of Hg(NO3)2 solution.
Summary -
1) determine the concentration (M) and density (g/mL) of the starting Hg(NO3)2 solution
2) determine the concentration (ppm) and volume (L) of your solution to be made.
3) Use these values in the equations shown above to determine the mass of the Hg(NO3)2 solution needed to make a ppm solution.
Simple.By test tube,pipette,beaker and with beam balance with test tube filled with the solution
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