Chem HW, limiting reactant?

A peice of Na metal (mass 8.20g) is burned in a jar that contains 20.62g Cl2 gas.

How many moles of Cl2 are initially present?

What is the limiting reactant?

How many grams of excess reactant remain unreacted in the jar after the reaction is completed?

The balanced chemical equation:

2 Na (s) + Cl2 (g) --> 2 NaCl (s)

Thank you so much for your help!!

Answer:
Molecular weight Cl2 = 70.91 g/mol
20.62 g/ 70.91 = 0.291 moles Cl2
Atomic weight Na = 22.9898 g/mol
8.20 g / 22.9898 = 0.357 moles Na
The ratio between Na and Cl is 2 : 1 so Na is the limiting reactant
2 : 1 = 0.357 : x
x = 0.178 moles Cl2 needed for the reaction
0.291 - 0.178 = 0.113 moles Cl2 in excess
0.113 mol x 70.91 g/mol = 8.01 g Cl2 unreacted
sodium is limited

left over Cl2 is 7.96g

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