Calculate the E° for the reaction Cd + Ni2+ —> Ni + Cd2+.?
Cd2+ + 2e- --> Cd E° = -0.402 V
Ni2+ + 2e- --> Ni E° = -0.236 V
Answer:
The reaction that occurs is :
Cd + Ni2+ >> Cd2+ + Ni
E° = + 0.402 - 0.236 = 0.166 V
Note : for the half-reaction of oxidation
Cd >> Cd2+ + 2e- E° = + 0.402 V
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Ni2+ + 2e- --> Ni E° = -0.236 V
Answer:
The reaction that occurs is :
Cd + Ni2+ >> Cd2+ + Ni
E° = + 0.402 - 0.236 = 0.166 V
Note : for the half-reaction of oxidation
Cd >> Cd2+ + 2e- E° = + 0.402 V
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