What is the reducing agent in the following oxidation-reduction equation?

MnO4– + H2SO3 + H+ —> Mn2+ + HSO4– + H2 O

Answer:
MnO4– + H2SO3 + H+ —> Mn2+ + HSO4– + H2O

Reducing agent is the species that becomes oxidised:
So either the one containing Mn, or S

Oxidation nos.
Mn before = + 7, after = +2
S before = +4, after = +6

Since S increases in oxidation number, H2SO3 is the reducing agent.
MnO4

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