Molarity word problem?
Answer:
M1 x V1 = M2 x V2
(12 M)(25.0 mL) = (M2)(225 mL)
[(300 mL-M) / (225 mL)] = M2
It's a dilution problem so you use
M1V1 = M2V2.
M1= Molarity of Solution 1
V1= Volume of Solution 1
M2= Molarity of Total Solution
V2= Volume of Total Solution
Plug in the numbers.
(12M HCl)(25.0mL) = (M2)(225 mL from 200+25)
You get 1.33 M
You start with 25.0mL of 12 M HCl
n = M * V = 12 mol/L * 0.025 L = 0.3 mol
This solution is diluted with 200 mL of distilled H2O
Total volume: 200 mL + 25 mL = 225 mL = 0.225 L
Molarity: M = n / V = 0.3 mol / 0.225 L = 1.333333 mol/L
End result: 1.333333 M HCL
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