What is the molecular weight of glucose if 22.5grams of glucose gives a frezing pnt oF–0.93°C when dissolved..
Answer:
The freezing point lowering is characteristic of the solvent and is directly proportional to the molal concentration of dissolved particles in the solution.
Kf for H2O = 1.86
delta T = m x kf
m = delta T / kf = 0.93 / 1.86 = 0.5
The solution is 0.5 m
m = moles / Kg solvent
0.5 = moles / 0.250
moles = 0.5 x 0.250 = 0.125
Molecular weight = 22.5 / 0.125 = 180 g/mol
C6H12O6
6(12)+1(1)+6(16)
72+1+36
109
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