To what temperature must 15 L of oxygen gas at 0°C be heated at 1 atm pressure in order to occupy a...?

To what temperature must 15 L of oxygen gas at 0°C be heated at 1 atm pressure in order to occupy a volume of 23 L, assuming that the pressure increases by 50 mm Hg?

Answer:
We use the equation
p1V1 / T1 = p2 V2 / T2

p1 = 1 atm
V1 = 15 L
T1 = 0 + 273 = 273 K

p2 = 1 + 50 / 760 = 1.066 atm
V2 = 23 L
T2 = ?

1 x 15 / 273 = 1.066 x 23 / T2

0.0549 = 24.5 / T2
T2 = 446.6 K = 173.6 °C
I have absolutely no idea, lol!

But would this link help at all?

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