What is the vapor pressure of a solution prepared by dissolving 100g of a nonvolatile solute (molar mass is 88 g/mol) in 30g of water?
Answer:
vapor pressure of solution = (mole fraction of solvent) x (vapor pressure of pure solvent)
100 g solute x (1 mol / 88 g) = 1.14 mol
30 g H2O x (1 mol / 18 g) = 1.67 mol
Mole fraction of H2O = (1.67 mol H2O)/(2.81 mol total) = 0.594
vapor pressure of solution = (0.594)(30) = 17.8 torr
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