Chem HM...oxidation/reduction?

For the equation:

Cu + 4HNO3 --> Cu(NO3)2 + 2 NO2 + 2 H2O

What is:

oxidized
reduced
the oxidizing agent
the reducing agent

Answer:
The oxidizing agent does the oxidizing, and is itself reduced in the process.

Look for something simple to start off with - usually a single atom or an element.

Cu becomes Cu2+ Its oxidation number goes from 0 on the left to +2 on the right when it is Copper Nitrate solution.

The oxidation number increases, so the Cu is OXIDIZED, so is the reducing agent.

Nitric acid is usually a powerful oxidizing agent, so that reinforces the answer.
oxidised - Cu = reducing agent
reduced - nitric acid (HNO3) = oxidizing agent
Let us 1st analyse the equation.Cu(metal) is converted to cupric ion .soits oxidation number has increased by 2 units. soit is oxidised . the oxidation number of nitrogen in HNO3 is +5. the oxidation number of nitrogen in NO2is+4. therefore its oxidation number has decreased by one unit .therefore it has been reduced .Now an oxidising agent oxidises a substance .HereHNO3 does the job.soitis an oxidising agentwhere as a reducing agent reduces a substance .Here Cu does the job.So it is the reducing agent.
copper is oxidised as its oxidation number increases from 0 to 2+

nitric acid is reduced as the oxidation number of hydrogen decreases from +1 to 0 as water molecule is neutral.

Copper is the reducing agent as it undergoes oxidation and it causes nitric acid to be reduced.

Nitric acid is the oxidising agent as it undergoes reduction and it oxidised copper.
Cu is oxidized
HNO3 is reduced
Cu is a reducing agent
HNO3 is a oxidizing agent

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