Calculate the solubility of FeS in water if the the Ksp= 1x 100 to the negative 22 power?



Answer:
The equilibrium is :
FeS <> Fe2+ + S2-
and the requirement for this equilibrium is that
Ksp = [Fe2+ ] [ S2-]
solubility = square root Ksp = 1 x 10^-10 M

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