How to calculate the percentage of oxygen in the compound (C8H9O2N)?

the numbers in the compound are atoms.
its the molecular formula of acetaminophen active ingredient in tylenol
i have to give the answer in three significant figures

Answer:
C8H9O2N
Mol.mass = 96 + 9 + 32 + 14 = 151
O2 = 32
32/151 = 0.2119 = 21.19% = 21.2% O2.
Find atomic weight of one molecule of the entire compound then the percentage oxygen is:

weight of oxygen in one molecule divided by total weight of one molecule
take the atomic mass of O and divide it by the entire mass of the compound

32/151= 0.211

multiply by 100=21.1%

the answer is 21.1 % of O

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