Two containers of gas with different amounts of moles but at equal temperature and pressure.?

If container "A" is occupied by 1.00 mole of oxygen gas while container "B" is occupied by 20.0 grams of nitrogen gas and both containers are maintained at 0.00 C and 650 torr then.

so i have a bunch of multiple choices to pick from:
1. The avg kinetic enery of the molecules in "a" is = to the avg kinetic energy of the molecules in b
2. container a must have volume of 22.4 L (so i used PV=nRT and figured out that its volume is 26.06 so that is ruled out, and also its not STP)
3. the avg speed of the molecules in container a is greater than those in container b
4. the # of atoms in container b is greater than the number of atoms in container a (for some reason, i thought this answer was too obvious because the temperature and pressure would not be used, so why were they given??)

also i calculated that 20.00 grams of Nitrogen is = to 1.4 moles

im sort of lost as to how to get the answer to this question now

Answer:
The answer to this question would be A. Basically the average kinetic energy of each container would be the same.

You are correct on answer B.

As for C, the average speed of the molecules is the same in both containers because they are both at constant pressure and temperature. Molecular speed is dependant on pressure and temperature.

As for D you are incorrect. Dont forget nitrogen is diatomic therefore there are 28 grams in one mole of nitrogen. therfore you have less than a mole of nitrogen as compared to one mole of oxygen.
Okay, you know that container "a" has 1mol of O2. Container "b" has 1.4mol of N2. That would mean #molecules in container "a" equals 5/7 the #molecules of container "b". Answer is 4

Oxygen is also diatomic man. H O N Cl Br I F are all diatomic
In container 'A' 1 mole of diatomic O2 (Mol.mass 32 = 32g/mol.) would occupy 22.4 L at STP. However, Pressure = 650torr.
650/760 = 0.855
0.855 x 22.4 = 19.41 L of O2

In container 'B' Nitrogen exists as a diatomic gas N2.
Its Mol.mass = 28. = 28g/mol.
Its mass is 20g.
20/28 = 0.714 moles of N2.
0.714 x 22.4 = 15.99 L of N2.

Which is your correct answer, ? ... I can't figure it, except to say that, as they're both at the same temperature and pressure, then answer 'A' is most likely.

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