How can I balance the following chemical equations?
H2 + N2 arrow NH3
Cl2 + KBr arrow Br2 + KCl
CH4 + O2 arrow CO2 + H2O
Fe + S arrow Fe2S3
P4 + H2 arrow PH3
NO + Cl2 arrow NOCl
SiCl4 + Mg arrow Si + MgCl2
Answer:
4Fe+3Oշ=2FeշOვ
6Hշ+Nշ=2NHვ
Clշ+2KBr=Brշ+2KCl
CH4+2Oշ=COշ+2HշO
2Fe+3S=FeշSვ
P4+6Hշ=4PHვ
2NO+Clշ=2NOCl
SiCl4+2Mg=Si+2MgClշ
3Fe + 202 arrow Fe2O3
3H2 + N2 arrow 2NH3
Cl2 + 2KBr arrow Br2 + 2KCl
CH4 + O2 arrow CO2 + 2H2O
2Fe + 3S arrow Fe2S3
P4 + 6H2 arrow 4PH3
2NO + Cl2 arrow 2NOCl
SiCl4 + 2Mg arrow Si + 2MgCl2
coefficients:
4, 3, 2
3, 1, 2
1, 2, 1, 2
1, 2, 1, 2
2, 3, 1
1, 6, 4
2, 1, 2
1, 2, 1, 2
4Fe + 3O2 -> 2Fe2O3
3H2 + N2 -> 2NH3
Cl2 + 2KBr -> Br2 + 2KCl
CH4 + 3O2 -> CO2 + 2H2O
2Fe + 3S -> Fe2S3
P4 + 6H2 -> 4PH3
2NO + Cl2 -> 2NOCl
SiCl4 + 2Mg -> Si + 2MgCl2
These are fairly easy chem equations..
2Fe + 3/2 O2 --->Fe2O3
3H2 + N2---->2NH3
Cl2 + 2KBr ----> Br2 + 2KCl
CH4 + 2O2 ---> CO2 + 2H2O
2Fe + 3S ---> Fe2S3
P4 + 6H2 ---> 4PH3
2NO + Cl2 ----> 2NOCl
SiCl4 + 2Mg -----> Si + 2MgCl2
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