This reaction: 2H2O2(g) ↔ 2H2O(g) + O2(g) reaches equilibrium with the concentrations [H2O2] = 0.55, [H2O] = 0.75, [O2] = 0.15, so what is the equilibrium constant for this reaction?
1) 0.37
2) 0.20
3) 0.28
4) 3.5
5) 0.15
Answer:
Equilibrium constant is definied as the ratio of the molar activities (concentrations) of the products to that of the reactants (multiplied). The coefficients become the power of exponents. So here,
K = [H2O]^2*[O2]/[H2O2]*2
just put in the values..
well, i'm not sure wich is wich but the formula is
Kc = [products] / [reagents] oops...forgot the squares it 3) 0.28
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