Draw structure?

when 2-butanol undergoes E1 dehydration, three alknes are obtained. draw the structures fpr these alkenes. which alkene would you predict to be formed in greatest abundance?

Answer:
Butene-1. C4H8
CH2=CH-CH2-CH3

cis. Butene-2. C4H8
CH3-C=C-CH3
....|...|
...H.H

trans. Butene-2 (Most abundant).
.....H
......|
CH3-C=C-CH3
.....|
....H

(Ignore the dotted lines).
Here are the 3 compounds:
1. trans-2-butene CH3CH=CHCH3 the double bond is trans
2. cis-2-butene CH3CH=CHCH3 the double bond is cis
3. 1-butene H2C=CHCH2CH3

Trans-2-butene will be formed in the greatest amount for the following two reasons: 1. Trans double bonds are least sterically hindered as compared to cis double bonds and 2. the more highly substituted a double bond is the more stable it is so the 2-butene will be more stable than 1-butene. Hope this helps. Good luck.
You will get 1 - butene (minor product) H2C=C(H)CH2CH2
cis - 2 - butene, (CH3)(H)C=C(H)CH3, the methyl groups will be on the same side of the molecule:

You also get trans-2-butene, CH3 groups will be on opposite sides



The major product should be the trans isomer, because the CH3 (methyl) groups are as far appart from each other.

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