So arsenics number is 33 and its weight is 74.92. whats the P, N, & E's? also what if it was negativly charged

I'm trying learning on my own... so if you could be really detailed and easy to understand, i'd apreciate it.

Thanks

Answer:
Hi blue achros!

I'm assuming that P = protons, N = neutrons, and E = electrons. If that's the case, then here goes:

The number of protons in an atom of an element is equal to the element's atomic number. Arsenic's atomic number is 33; therefore, the atom of arsenic (As) has 33 protons.

To determine the number of neutrons, subtract the number of protons from the atomic weight (W - P = N). In this case, the weight is a decimal (meaning it can have different numbers of neutrons), so the best option here is to round 74.92 up to 75, then subtract: 75 - 33 = 42 neutrons.

The number of electrons in an atom is (normally) equal to the number of protons. Arsenic, therefore, has 33 electrons.

So, one atom of arsenic should have 33 protons, 33 electrons, and 42 neutrons.

If the atom was negatively charged, it would be an ion. The negative charge means that there would be more negative charges (electrons) on the atom than positive charges (protons).

Hope that helped out!
Atomic NUmber = # of electrons = # of protons == 33

Atomic weight = P+N
N = Atomic weight - P = 75 - 33 = 42 (round up, because atomic weight is the average of a number of isotopes.)

If negatively charged:
P = 33 (no change)
N=42 (no change)
E = 34 (Negatively charged means E > P)

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