Please help me with Chem problem 3?

Calculate the molarity (M) of the following solutions...

A) 2.0 moles glucose in 4.0 L of solution

B) 4.0 g KOH in 2.0 L of solution

Please show work

Answer:
Molarity = moles /L

A) 2.0 / 4.0 = 0.5 M

B) 4.0 g / 56 g/mol = 0.0714 moles

0.0714 /2 = 0.0357 M

56 g/mol = MM KOH
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