What is the equation for sodium hydroxide and hydrochloric acid?
Answer:
Moles
Concentrations of Solutions.
The concentration of a solution is a measure of
the number of particles of the solute in the solvent.
A concentrated solution will have
a large number of particles of the solute in the solvent.
A dilute solution will have
a small number of particles of the solute in the solvent.
Concentrations can be expressed as mol dm-3 or grams per dm3.
The number of moles of solute in solution is given by the formula
moles = (C x V) ÷ 1000
where C = concentration in mol dm-3 (moles per dm3).
V = volume in cm3.
Example 1.
In a titration, 50 cm3 of 2 mol dm-3 sodium hydroxide
was exactly neutralised by 30 cm3 of hydrochloric acid.
What is the concentration of the hydrochloric acid?
Method.
1) Write the equation for the reaction.
sodium hydroxide + hydrochloric acid sodium chloride + water.
NaOH(aq) + HCl(aq) NaCl(aq) + H2O(l)
Use the big numbers to find the proportion of NaOH to HCl.
One mole of NaOH reacts with one mole of HCl.
2) Find how many moles of sodium hydroxide are present.
moles = (C x V) ÷ 1000.
The number of moles in 50 cm3 of 2 mol dm-3 sodium hydroxide
= (2 x 50) ÷ 1000
= 0·1 moles of sodium hydroxide.
3) From 1 and 2, 30 cm3 of hydrochloric acid
also contains 0·1 moles.
You can rearrange moles = (C x V) ÷ 1000 to give
C = (moles x 1000) ÷ V
C = (0·1 x 1000) ÷ 30
= 3·33.
The concentration of hydrochloric acid is 3·33 mol dm-3
NaOH+HCl---->NaCl+H2O
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NaOH+HCl------>NaCl+H2o (neutralization reaction its opposite is called hydrolysis reaction )
the net ionic equation is OH- (aq) + H+ (aq) --> H2O (l)
NaOH+HCl ---> H20+NaCl
NAOH is sodium hydroxide and HCL is hydrochloric acid
NaOH + HCL ----> NaCl + H2O
the ionic equation is H+ + OH- ----> H2O
did u meant sodium hydroxide+hydrochloric acid?
NaOH + HCl ---> NaCl + H20
NaOH + HCl = NaCl + H2O
This is the classic acid + alkali gives a salt + water.
In Words,
Sodium Hydroxide plus Hydrochloric Acid gives Sodium Chloride plus water.
Na oH + HCl-----------> NaCl + H2O
NaOH+HCl ---> NaCl + H2O
NaOH(aq) + HCl(aq) >>>>NaCl (aq) + H2O (l)
Sodium Hydroxide is NaOH
Hydrochloric Acid is HCl
NaOH (aq) + HCl (aq) >>>>NaCl (aq) +H2O (aq)
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