Daltons law..please answer..?

a tank contains 78.0 g N2 and 42 g Ne at a total pressure of 3.75 atm and a temp. of 50.0 C. Calculate. the ff:
moles of N2
moles of Ne
partial pressure of N2
part.pressure of Ne

Answer:
Molecular weight N2 = 28 g/mol
78.0 /28 = 2.78 moles N2
Atomic weight Ne = 20.2 g/mol
42 g / 20.2 = 2.08 moles Ne

Total moles = 2.78 + 2.08 = 4.86

p(N2) / p (T) = n (N2) / n (T)
p (N2) / 3.75 = 2.78 / 4.86

p(N2) = 2.14 atm

p(Ne) / 3.75 = 2.08 / 4.86

p(Ne) = 1.60 atm
hold on, let me check my books. I'll be right back

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