A sample of gas at 38.0 degrees C occupies a volume of 2.97 L and exerts a pressure of 3.14 atm. The gas is heated to 118.0 degrees C and the volume is decreased to 1.04 L. Determine the new pressure exerted by the gas. (convert temperature to K before substituting in equation)
Answer:
We can use the equation
p1V1 / T1 = p2V2 / T2
T1 = 38 + 273 = 311 K
T2 = 118 + 273 = 391 K
3.14 x 2.97 / 311 = p2 x 1.04 / 391
0.00340 = p2 x 0.00266
p2 = 11.3 atm
you have pV =nRT
in condition(1) p1 V1= nRT1
in condition(2) p2V2= nRT2
so p2V2/p1V1= T2/T1 p2V2T1 =p1V1T2 ; p2=p1V1T2/V2T1
here T1 =38+273=311K T2 = 118+273=391K
V1 =2.97L V2 = 2.97-1.04= 1.93L
so p2 = 3.14*391*3.14/(1.93*311)=6.43 atm
the eqn u need is P1V1/T1 =P2V2/T2
PLUG IN THE NUMBERS YOURSELF LAZY A**!
The answers post by the user, for information only, FunQA.com does not guarantee the right.
More Questions and Answers:
Explain.time is gold?
The solubility of lead chloride PbCl2 is 1.6x10^-2M. What is the Ksp of PbCl2?
When platinum is placed in aqua regia solution (mixture of HCl and HNO3), the following redox equation...?
How many liters of hydrogen (N2) are needed to produce 100 liters of ammonia (NH3) by direct combination with?
I found a 1964 quarter that feels really light and different than a regular quarter is it worth anything?
How is sand made?
New methods for use of waste materials?
Calculate molar mass?
What is the standard voltage of tin being oxidized?