50.0 grams of KClO3 solid is heated and the following reaction occurs:?

2KClO3(s) → 2KCl(s) + 3O2(g)

If the O2 produced is sealed in a 5.00L container at 35.0oC, what is the pressure in the container in atmospheres?

Answer:
KClO3 = 39.1 + 35.5 + 48 = 122.6 g/mol
50 g / 122.6 g/mol = 0.41 mol KClO3
0.41 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 0.61 mol O2
PV=nRT
P = nRT/V = 0.61 mol (0.0821 L atm / mol K) (35 + 273.15 K) / 5 L
= 3.1 atm

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