What is the oxidation number of the following?
K2CrO4--> C
BrO2--> Br
Na2CO3--> C
H2O2--> O
Answer:
hi
finding out oxidation states of comounds is the easiest thing.
i will help u out....
make sure u know the basic..
N =+4
Cr =+6
Br =+4
C =+4
O= -1
ANSWERS
1) NO2---N
let us take N as x
so finding out....
we get,
x - 4 = 0
x=+4
therfore the oxidation state of notogen is +4
Answers -2)
K2CrO4--> Cr
let Cr be x
now..we can say that,
2 + x -2(4)=0
2 + x - 8 = 0
x-6=0
x=+6
therfore the oxidation state is +6
Answer-3)
let Br be x
x-2(2)=0
x=+4
therfore bromine show osxidation state of +4
Answer-4)
let C be x...
2 + x - 3(2)=0
2 + x-6=0
x=+4
therefore C shows +4 oxidation state....
Answer-5)
let O be x
2 + 2x = 0
x = -1
its a peroxide linkage
therefore O shows an oxidation state of -1
NOTE------
ALWAYS EQUATE IT TO ZERO,...
IF THERE IS A CHARGE ...EQUATE IT TO CHARGE
LEARN THE VEALENCIES PROPERLY...
like K is 1
O is -1,-2
Cl is -1 etc...
hope this is the best answer.,.
all the best....
N = +4
Cr = +6
Br = +4
C = +4
O = +1
N +2
Cr +6
Br +4
C +4
O -1
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