What is the oxidation number of the following?

NO2--> N
K2CrO4--> C
BrO2--> Br
Na2CO3--> C
H2O2--> O

Answer:
hi
finding out oxidation states of comounds is the easiest thing.

i will help u out....
make sure u know the basic..

N =+4

Cr =+6

Br =+4

C =+4

O= -1



ANSWERS

1) NO2---N

let us take N as x

so finding out....
we get,

x - 4 = 0
x=+4

therfore the oxidation state of notogen is +4

Answers -2)

K2CrO4--> Cr

let Cr be x
now..we can say that,

2 + x -2(4)=0
2 + x - 8 = 0
x-6=0
x=+6

therfore the oxidation state is +6

Answer-3)
let Br be x

x-2(2)=0
x=+4

therfore bromine show osxidation state of +4

Answer-4)

let C be x...
2 + x - 3(2)=0
2 + x-6=0
x=+4

therefore C shows +4 oxidation state....

Answer-5)

let O be x
2 + 2x = 0
x = -1

its a peroxide linkage

therefore O shows an oxidation state of -1

NOTE------
ALWAYS EQUATE IT TO ZERO,...
IF THERE IS A CHARGE ...EQUATE IT TO CHARGE
LEARN THE VEALENCIES PROPERLY...
like K is 1
O is -1,-2
Cl is -1 etc...

hope this is the best answer.,.
all the best....
N = +4
Cr = +6
Br = +4
C = +4
O = +1
N +2

Cr +6

Br +4

C +4

O -1

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