The Volume of 0.50 M BaCl2,which contains 3 moles of Cl- ions?

please help!

Answer:
BaCl2 --> Ba2+ + 2Cl-

if there are 3 mol Cl-, then there must be 3/2 mol BaCl2 by stoichiometry.

0.50 M means 0.5 moles per liter

you know that there are 1.5 mol, so

1.5 mol/? L = 0.5 mol/1 L

simple proportion

? L=1*1.5/0.5=3

3 liters <---answer
volume = no of moles/molar volume
so find molar volume= no of moles/molecular weight
moles =molarity x vol
so 3 lit is the ans
BaCl2 ionises in aqueous solution as shown below.
BaCl2 =Ba(2+) + 2Cl(-)
So, a 0.5M solution with respect to the salt is identical to a 1M solution withe respect to the chloride ion.Hence -
1 mole of Cl- ion = 1 litre of the solution
3 moles of Cl- ions = ?
= 3 litres

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