Silicon Tetraflouride?
How many grams of silicon tetraflouride, a gas, at room temperature, would fill the same volume as that occupied by 350 grams of carbon monoxide at 75C and 575 torr?
Answer:
Use the ideal gas law to find it PV=nRT
CO MW = 28.0101 g/mole
SiF MW = 104.08 g/mole
R = 62.364 L •Torr/ K • mole
Part one, find the volume from the first data for CO
350 g/28.0101g/mole = 12.4955 mole
P = 575 Torr
T = 75 ºC + 273 = 348 K
V = nRT/P = (12.4995 mole) (62.364 L •Torr/ K • mole) (348 K) / 575 Torr
= 471.78 L
Now use this Volume to find the moles and grams of SiF4
P = 760 Torr
V= 471.78 L
T = 25ºC + 273 = 298 K
n = PV/RT = (760 Torr) (471.78 L) / (62.364 L •Torr/ K • mole) (298 K)
= 19.29 moles
19.29 mole SiF4 * (104.08g/mole) = 2008g
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Answer:
Use the ideal gas law to find it PV=nRT
CO MW = 28.0101 g/mole
SiF MW = 104.08 g/mole
R = 62.364 L •Torr/ K • mole
Part one, find the volume from the first data for CO
350 g/28.0101g/mole = 12.4955 mole
P = 575 Torr
T = 75 ºC + 273 = 348 K
V = nRT/P = (12.4995 mole) (62.364 L •Torr/ K • mole) (348 K) / 575 Torr
= 471.78 L
Now use this Volume to find the moles and grams of SiF4
P = 760 Torr
V= 471.78 L
T = 25ºC + 273 = 298 K
n = PV/RT = (760 Torr) (471.78 L) / (62.364 L •Torr/ K • mole) (298 K)
= 19.29 moles
19.29 mole SiF4 * (104.08g/mole) = 2008g
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