Chemistry help?

the solubility of barium hydroxide in water at 20degrees C is 1.85g/100g water. A solution is made up of 256 mg in 35.0 g of water. Is the solution saturated. If not, how much more barium hydroxide needs to be added to make a saturated solution?

Answer:
If 1.85gBa(OH)2 is needed to saturate with 100g water, then with 35g water: 35gH2O x 1.85gBa(OH)2/100gH2O = .6457gBa(OH)2 (=645.7mg) needed to saturate the solution. The solution, therefore, is not saturated and you need an additional 389.7mg (or .3897g) of barium hydroxide to saturate the solution.
256 mg = 0.256 g
0.256 g / 35.0 g water is the same concentration as 0.256/0.35 per 100 g water or 0.731 g so the solution isn't saturated.
A saturated solution would contain 1.85 g / 100 g water or 0.35x1.85 g per 35 g of water or 0.6475 g. You would need to add 0.6475-0.256 or 0.3915 g more of barium hydroxide to obtain a saturated solution in 35 g water.
256 mg/35 g = 731.4 mg/ 100g
means that the solution has not saturated yet. Because it should be 1.85g/100g to be saturated.

1.85g/100g = 0.6475g/35g = 647.5mg/35g

To make it saturated u have to add:
(647.5 - 256) = 391.5 mg Ba(OH)2

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