What is the product of this chemical equation?
I have two solutions, Na2CO3 and HCL, that were added together to form a product. What would be the chemical equations of the products? Na2Cl is not possible so I'm not sure how to answer this.
Answer:
Here is the balanced chemical equation for the reaction of sodium carbonate and hydrochloric acid:
Na2CO3 + 2HCl ---> 2NaCl + H2O + CO2
You're right. Na2Cl is not a possible product - it can only be NaCl. So the way to make the equation balanced on both sides is to use what is called a "coefficent" in front of the molecule necessary. For example, you probably noticed that I put a coefficent of "2" in front of the "HCl" and a "2" in front of the "NaCl." The reason is so that there will be equal amounts of each element on both sides of the equation. You can't change is actual formula of NaCl because if you do change it to Na2Cl, you are actually changing sodium chloride into some other compound and it won't be salt anymore. For example, carbon dioxide has a formula of CO2 (which is a non-toxic gas that we breathe from the air). But if you remove the "2" subscript, it will change to CO, carbon monoxide (which is a really toxic gas that is produced from a car's engine!)
So we use coefficents in front of the molecule in order to balance the equation, rather than changing the subscripts.
------------------------------...
I hope this helps.
Na2CO3 + 2HCl ==> 2NaCl(aq) + H2O(l) + CO2(g)
HCO3 just naturally splits up that way, otherwise just switch cations, correct for charges, and balance.
Here is the balanced equation:
Na2CO3 + 2HCl --------> 2NaCl + H2CO3
You form sodium chloride and carbonic acid. Carbonic acid is not stable at room temperature so it can further dissociate as Cheryl N said. Hope this helps.
The second formula is spot on.
Na2CO3(aq) + 2HCl(aq) --> 2NaCl(aq) + H2CO3(aq)
-------------- --------------- OR -------------- ----------------
Na2CO3(aq) + 2HCl(aq) --> 2NaCl(aq) + CO2(g) + H2O(l)
Because Na2Cl is not possible. U have to think what compounds should it be. And of course it's NaCl.
there are 2 Na, but only one Cl. So what u have to do is make the Cl become 2. Add 2 as the coeficient in HCl. SO there are 2 Cl now.
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Answer:
Here is the balanced chemical equation for the reaction of sodium carbonate and hydrochloric acid:
Na2CO3 + 2HCl ---> 2NaCl + H2O + CO2
You're right. Na2Cl is not a possible product - it can only be NaCl. So the way to make the equation balanced on both sides is to use what is called a "coefficent" in front of the molecule necessary. For example, you probably noticed that I put a coefficent of "2" in front of the "HCl" and a "2" in front of the "NaCl." The reason is so that there will be equal amounts of each element on both sides of the equation. You can't change is actual formula of NaCl because if you do change it to Na2Cl, you are actually changing sodium chloride into some other compound and it won't be salt anymore. For example, carbon dioxide has a formula of CO2 (which is a non-toxic gas that we breathe from the air). But if you remove the "2" subscript, it will change to CO, carbon monoxide (which is a really toxic gas that is produced from a car's engine!)
So we use coefficents in front of the molecule in order to balance the equation, rather than changing the subscripts.
------------------------------...
I hope this helps.
Na2CO3 + 2HCl ==> 2NaCl(aq) + H2O(l) + CO2(g)
HCO3 just naturally splits up that way, otherwise just switch cations, correct for charges, and balance.
Here is the balanced equation:
Na2CO3 + 2HCl --------> 2NaCl + H2CO3
You form sodium chloride and carbonic acid. Carbonic acid is not stable at room temperature so it can further dissociate as Cheryl N said. Hope this helps.
The second formula is spot on.
Na2CO3(aq) + 2HCl(aq) --> 2NaCl(aq) + H2CO3(aq)
-------------- --------------- OR -------------- ----------------
Na2CO3(aq) + 2HCl(aq) --> 2NaCl(aq) + CO2(g) + H2O(l)
Because Na2Cl is not possible. U have to think what compounds should it be. And of course it's NaCl.
there are 2 Na, but only one Cl. So what u have to do is make the Cl become 2. Add 2 as the coeficient in HCl. SO there are 2 Cl now.
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