Molarity concentration?

Considering that volumes are additive, what is the concentration of KBr in a solution prepared by mixing 0.237 L of 0.033 M KBr with 0.634 L of 0.082 M of KBr?

Answer:
.237 L x .033 mol/L = .007821 mol KBr
.634 L x .082 mol/L = .051988 mol KBr
.007821 + .051988 = .059809 mol KBr total

.059809 /(.237L + .634L) = .0687 M KBr

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