Assuming complete dissociation of the solute, how many grams of must be added to 275 of water to produce a solution that freezes at 14.5 ? The freezing point for pure water is 0.0 and is equal to 1.86 .
Answer:
The formula id
Delta T = kf x m x i
i is the number of ions dissolved
( for example for NaCl i = 2 , for Ca(NO3)2 i = 3 )
If I don't know the solute I can not know i
14.5 = 1.86 x m x i
7.85 = m x i
m = moles solute / Kg water = moles solute / 0.275
If we suppose i = 1
m = 7.85 = moles / 0.275
moles = 2.16
As I can see in the problem there is the compound because now to get grams I must know its molecular weight
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