Calculate the number of moles of oxygen produced when 6.75 mol of manganese dioxide decomposes to Mn3O2 + O2:?

3 MnO2(s) ---> Mn3O4(s) + O2(g)

I don't even know where to begin; any help would be appreciated :]

Answer:
Always start with the value they give you. Then, just go to the reaction in this case.

(6.75 mol MnO2)( 1 mol O2/3 moles MnO2) = 2.25 moles O2 produced

here u can see in the balanced eq. that 3 moles of MnO2 is capable of producing 1 mole of O2
so
3-------1
6.25---?
?=1*6.25/3= 2.25

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Calculate the number of moles of oxygen produced when 6.75 mol of manganese dioxide decomposes to Mn3O2 + O2:?

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