Consider the equilibrium reaction : A(g) <-- --> 2B(g) + C(g)?

When 1.00 mol of A is placed in a 4.00L container at temperature t , the concentration of C at equilibrium is 0.050 mol/L. What is the equilibrium constant for the reaction at temperature t?

Answer:
Since the equilibrium constant K = (B^2 * C)/A

and we have .05 * 4 = .2 Mol of C and .1 Mol of B and the amount of A left is .8 Mol then K = .(.1^2 * .2)/.8 = .0025

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