OK this is like really hard. Does anyone have an idea on this?
empirical formula
molecular formula
Answer:
empirical formula-C8H8O3
because:
C-(63.15g/mol)(1 mol/12g)=5.26 mol C x3 = 16 mol/2 mol
H- (5.30g/mol)(1 mol/1g)=5.3 mol H x3= 16 mol/2 mol
O- (31.55g/mol) (1 mol/16g)=2 mol O x3= 6 mol/2 mol
C8H8O3
molecular formula- 152 g/mol. Subtract 8 carbons, 8 hydrogens and 3 oxygens from 152. if you get zero, which you do, then you're done. if not, subtract 16 carbons, 16 hydrogens and 6 oxygens, if you don't get to zero yet, keep adding more and more until you get to zero.
is his homework??:)
48 + 8 +96 = 152 = 100%
O (48*100)/152 = 31.5%
H (8*100)/152 = 5.3%
C (96*100)/152 = 63.15%
C = 12
12*8 = 96
H = 1
1 * 8 = 8
O = 16
3 * 16 = 48
C8H8O3 empirical and molecular
C = .6315 X152.4 /12 = 8
H =.053 x 152.14 /1.008 = 8
O = .3155 x152.14 /16 =3
C8H8O3
C6H5CH(OH)COOH
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