Depict the electron configuration for the low spin cobalt complex [Co(NH3)6]3+ and determine the numbers of unpaired electrons are present. Describe the complex as paramagnetic or diamagnetic.
Answer:
Cobalt is in the +3 oxidation state so its electron configuration is 3d6. In this octahedral complex, the cobalt ion takes on the electron configuration (3t2g)(6) (3eg)(0). (Three orbitals below, all filled with pairs of electrons, two above, empty). Thus there are no unpaired electrons and the hexaamminecobalt(III) ion is diamagnetic.
co=1 N=1 H3=3 1+3=4x6=24....and I have no clue....you didn't right that...it barly makes sence.
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