Chemistry help?

A) Determine the number of grams in 0.750 moles of the compound Iron (II) phosphate: Fe^3(PO^4)^2.

B) How many atoms of iron are in 0.650 moles of the compound Iron (III) oxide?

Answer:
Molar mass Fe3(PO4)2 = 357.48 g/mol
0.750 mol x 357.48 g/mol = 268.1 g

Iron (III) oxide is Fe2O3
In 0.650 moles of Fe2O3 there are 0.650 x 2 = 1.30 moles of Fe
1 mole : 6.02 x10^23 = 1.30 : x
x = 7.83 x 10^23 atoms of Fe

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