Aluminum reacts with sulfuric acid, which is the acid in automoblie batteries. If 20.0 grams of Al is placed into a slution containing 115 grams of H2SO4, how many grams of hydrogen gas could be produced?
Can anyone help?
Answer:
The balanced reaction is :
2Al +3 H2SO4 >> Al2(SO4)3 +3 H2
Atomic mass Al = 26.98 g/mol
20.0 g / 26.98 = 0.741 moles Al
Molecular mass H2SO4 = 98 g/mol
115 / 98 = 1.17 moles H2SO4
The ratio between Al and H2SO4 is 2 : 3
2 : 3 = 0.741 : x
x = 1.11 moles H2SO4 needed for the reaction
Since we have 1.17 moles of H2SO4 Al is the limiting reactant
The ratio between Al ( limiting reactant ) and H2 is 2 : 3
2 : 3 = 0.741 : x
x = 1.11 moles H2 produced
Molecula mass H2 = 2 g/mol
1.11 mol x 2 g/mol = 2.22 g
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