If the O2 produced is selaed in a 5.00L container at 35, 0deg C What's the pressure in the container in atmosp
if the O2 produced is sealed in a 5.00L container at 35, 0 degrees C what is the pressure in the container in atmospheres?
Answer:
KClO3 = 39.1 + 35.5 + 48 = 122.6 g/mol
50 g / 122.6 g/mol = 0.41 mol KClO3
0.41 mol KClO3 * (3 mol O2 / 2 mol KClO3) = 0.61 mol O2
PV=nRT
P = nRT/V = 0.61 mol (0.0821 L atm / mol K) (35 + 273.15 K) / 5 L
= 3.1 atm
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