The pH of an acid solution should decrease with concentration. Given that K(f) for acetic acid is 1.76E-5, find the pH of HAc and HCl solutions of concentration:
a) 0.00010 M
b) 0.0010 M
Answer:
CH3COOH <> CH3COO- + H+
initial conc
0.00010
at eq.
0.00010 -x . . . . . .. . x . .. . . . . x
Ka = 1.76 x 10^-5 = x^2 / 0.00010-x
x = 0.0000419
pH = - log 0.000419 = 4.38
in the same way pH of acetic acid 0.0010 M = 3.87
HCl >> H+ + Cl-
pH = - log 0.00010 = 4
pH = - log 0.0010 = 3
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