Al(NO3)3 + 3NaOH --> Al(OH)3 + 3NaNO3?

First:NaOH is added to Al(NO3)3
Second:Result>>a white precipitate is formed.
Third:The white precipitate is soluble in excess NaOH solution.


Aluminum hydroxide dissolves in strong alkali to form:

Al(OH)3(s) + OH-(aq) --> Al(OH)4-(aq)

The white precipitate is of aluminium hydroxide which is soluble in the excess of NaOH because it can form Hydrogen bond.
Al(OH)3 is insoluble. It is soluble in excess OH- however. This is faily common; if you have an insoluble ion, adding a soluble ion may make it soluble.

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