A mole question?

25cm3 of a dibasic acid solution containing 4.9gdm-3 reacted with 25cm3 of a solution of a base of concentration 0.50moldm-3. What is the relative molecular mass of the acid?

Answer:
as the volume is same ,and acid is dibasic
conc. of acid =(1/2)of base
=(1/4)M
M=mol/dm-3

strength=concentration * molar mass

4.9g/l=(1/4)mol/l * W

W= 19.6 g/mol
as the volume is same ,and acid is dibasic
conc. of acid =(1/2)of base
=(1/4)M
M=mol/dm-3

strength=concentration * molar mass

4.9g/l=(1/4)mol/l * W

W= 19.6 g/mol

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